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16x^2=1936
We move all terms to the left:
16x^2-(1936)=0
a = 16; b = 0; c = -1936;
Δ = b2-4ac
Δ = 02-4·16·(-1936)
Δ = 123904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{123904}=352$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-352}{2*16}=\frac{-352}{32} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+352}{2*16}=\frac{352}{32} =11 $
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